b^2+16b-225=0

Solution for b^2+16b-225=0 equation:

Simplifying
b2 + 16b + -225 = 0

Reorder the terms:
-225 + 16b + b2 = 0

Solving
-225 + 16b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-25 + -1b)(9 + -1b) = 0

Subproblem 1
Set the factor '(-25 + -1b)' equal to zero and attempt to solve:

Simplifying
-25 + -1b = 0

Solving
-25 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + -1b = 0 + 25

Combine like terms: -25 + 25 = 0
0 + -1b = 0 + 25
-1b = 0 + 25

Combine like terms: 0 + 25 = 25
-1b = 25

Divide each side by '-1'.
b = -25

Simplifying
b = -25
Subproblem 2
Set the factor '(9 + -1b)' equal to zero and attempt to solve:

Simplifying
9 + -1b = 0

Solving
9 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1b = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -1b = 0 + -9
-1b = 0 + -9

Combine like terms: 0 + -9 = -9
-1b = -9

Divide each side by '-1'.
b = 9

Simplifying
b = 9
Solution
b = {-25, 9}